If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4.9x^2-15x-40=0
a = 4.9; b = -15; c = -40;
Δ = b2-4ac
Δ = -152-4·4.9·(-40)
Δ = 1009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{1009}}{2*4.9}=\frac{15-\sqrt{1009}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{1009}}{2*4.9}=\frac{15+\sqrt{1009}}{9.8} $
| 31-3m=10 | | 2(a-1)-3=-4-1 | | 1/3n=1/4=1/2 | | 19x-4(5x-7)=34 | | -9/15x=35/15 | | 10x-5/5=2x-1 | | 0.69x+18=1.29x | | 0.01x+2.79=2.03x-1.25 | | 8a-52=-5a | | 5x+10=50+3x | | `0.75x-0.5=x+1.5` | | -2(6y)+7y=15 | | 15x+10=180-50 | | 20=85x | | 12(x-12)=-8 | | -1.5x+5=20 | | -3/2x+5=20 | | 3(1000000)^2=x | | 52a+1=35 | | 0.6/x=3/25 | | k+619,k=11 | | 2x/10-4=5 | | 5x-(2x+3)=4-(x-1) | | x+32+2x=44 | | 8a^2-8a-1=0 | | 5/2x+3/5=3/10x | | 2p+29=90 | | 54=3/4(x+6 | | 3+62n+1-4n=25 | | x/0.5+8.6=-3.5 | | 3*(0.6+x)=6 | | t/−11=11 |